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The Definition of Firepower ?

Discussion in 'The Tanks of World War 2' started by Skua, Sep 26, 2004.

  1. GP

    GP New Member

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    Using this senario the 50 mm shells would penetrate the 80 mm armoured tank but not the other way round. So in this particular instance no but generally yes.

    To give a better answer would require more specs on both tanks as one would require the acuracy and rate of fire etc for the full potential to be realised.
     
  2. Gothard phpbb3

    Gothard phpbb3 New Member

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    my point exactly. therefore firepower cant be determined solely by the weapon. "potential" firepower is impossible to determine without weighing in the other factors involved. And by that standard, determing true "potential" firepower means determing the "effective" firepower given the circumstances and then going backwards to determine per unit "potential"
     
  3. GP

    GP New Member

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    I have never said otherwise.

    Just that people are mixing firepower with killing power.

    MHO

    Fire power is what it can do, killing power is what it can do with the crew it has.
     
  4. Gothard phpbb3

    Gothard phpbb3 New Member

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    weve already decided that potential is the raw weapon. and effective is the raw weapon plus crew, optics and other mitigating factors.

    a 50mm can potentially penetrate 90mm of armor. period.
    to determine killing power you need to factor in the crews effectiveness, the enemy protection etc...
     
  5. Gothard phpbb3

    Gothard phpbb3 New Member

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    back to the Topic.

    Define Firepower.

    there should be a mathematical formula to dtermine firepower.
     
  6. GP

    GP New Member

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    ]

    There probably is but you would have to be a sad b'stard to work it out........


    Now where is Greg?

    LOL
     
  7. Gothard phpbb3

    Gothard phpbb3 New Member

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    What are the variables ?

    1. Friendly factors
    2. Enemy factors
    3. Neutral factors.


    1. Friendly = Calibre
    Velocity
    Ammo type
    which together equal penetration
    so A ( calibre ) x B ( Velocity ) + C ( Ammo Type ) = D ( Penetration )
    Now Deduct E. Enemy armor thickness F. Enemy armor Slope G. Enemy Armor type H. Speed of target

    from this ya can determine "potential" firepower.
    the firepower delivered under a given set of circumstances.

    a shell of w calibre travelling at x velocity of y weight and composed of x ammo type Impacting on armor a thick at b angle against ( Face hardened ? spaced ? etc.. ) armor moving at 20 MPH in rolling terrain.

    ya know a straight comparison of potential impact is possible given a hit at an exact point on a non moving target.

    being able to track the target and fire repeatedly until the target is penetrated is another matter.

    in this case if theres a 1 in 5 chance of penetration... and ya have 1 vehicle.. ya have 20% effective firepower.
    if ya have 5 vehicles communicating by radio and firing on the same target... ya have 100% effective firepower.
     
  8. Notmi

    Notmi New Member

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    Sorry, that was a "bit" of the line. My bad.
     

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